PHP和SQL —从数据库中选择

Question

I have a problem with this code. It has syntax error and I don't know what is it.

<?php
$host = 'localhost';
$user = 'root';
$pass = '';
$db = 'id1381007_accounts';
$conn = new mysqli($host,$user,$pass,$db) or die($mysqli->error);

if (!$conn) {
die('Could not connect: ' . mysql_error());

$sql  = 'SELECT id FROM users WHERE email=\"donat12@icloud.com\"';

echo $sql;
?>

Answer 1

There are some issue with the code. First you forgot to close the if condition over here

if (!$conn) {

And then you forgot to execute the sql query

the complete code would be like

<?php
$host = 'localhost';
$user = 'root';
$pass = '';
$db = 'id1381007_accounts';
$conn = new mysqli($host,$user,$pass,$db) or die($mysqli->error);

if (!$conn) {
 die('Could not connect: ' . mysql_error());
}
$sql  = 'SELECT id FROM users WHERE email=\"donat12@icloud.com\"';
if ($result = $conn->query($sql)) {
   while ( $row = $result->fetch_assoc()) {
        $data[] = $row;
    }
    echo "<pre>";
    print_r($data);
    echo "</pre>";
}
$conn->close();
?>

Answer 2

There are two errors

1. You are missing } closing bracket after die
2. Mysql query is wrong.

So the code should be

if (!$conn) {
die('Could not connect: ' . mysql_error());
}
$sql  = 'SELECT id FROM users WHERE email="donat12@icloud.com"';

echo $sql;