打开功能不返回文件描述符

Question

Python open function does not return file descriptor. Why could this be? I am using python 3.3.

test_file_open.py

#!/usr/bin/env python

import sys
if __name__ == '__main__':
    html = ""
    hmtl_fd = open("ns_temp.html",'r')
    for line in html_fd:
        html += line

Output:

Traceback (most recent call last):
  File "./test_file_open.py", line 7, in <module>
    for line in html_fd:
NameError: name 'html_fd' is not defined

Permissions:

-rwxr-xr-x 1 michael michael 160 Mar 16 23:03 test_file_open.py

Answer 1

There is a typo in a variable name, see hmtl_fd and html_fd .

Replace:

hmtl_fd = open("ns_temp.html",'r')

with:

html_fd = open("ns_temp.html",'r')

Answer 2

hmtl_fd ：用hmtl_fd代替html_fd