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地图运算符[]的编译错误

[英]Compile error for map operator []

Why do I get a compile error for "recMap[key] = rec;" 为什么会出现“ recMap [key] = rec;”的编译错误? in the below code but the equivalent statements work fine? 在下面的代码中,但等效的语句工作正常吗? I have other code that does this. 我还有其他代码可以做到这一点。 What simple thing am I missing? 我缺少什么简单的东西?

#include <map>

class MyRec {
   public:
   MyRec(int numberIn) : myNumber(numberIn) { };
   int myNumber;
};

int main(int argc, char **argv)
{
   typedef std::map<int, MyRec> Recs;
   Recs recMap;
   int num=104702;
   int key=100923;

   MyRec rec(num);

   recMap[key] = rec; // Doesn't compile
   // error: no matching function for call to MyRec::MyRec()
   // samp.cpp:5: note: candidates are: MyRec::MyRec(int)
   // samp.cpp:3: note:                 MyRec::MyRec(const MyRec&)

   // Why do I receive the compile error for the above if it is the same as:
   (*((recMap.insert(std::make_pair(key,rec))).first)).second;

   recMap.insert(std::pair<int, MyRec>(key,rec)); // Works also of course
}

Consider this snippet: 请考虑以下代码段:

std::map<int, Foo> map;
map[0];

This will actually work fine even if havent inserted an object for key 0. The reason is, that there is a difference between std::map::at() and std::map::operator []() : 即使没有为键0插入对象,这实际上也可以正常工作。原因是std::map::at()std::map::operator []()之间存在差异:

std::map::at() only returns a reference to an object inside the map. std::map::at()仅返回对地图内部对象的引用。 If there isnt an object for the given key, an exception is thrown. 如果没有给定键的对象,则会引发异常。

std::map::operator []() does also return a reference, however if there no object for the given key, it creates an object inside the map and returns a reference to this newly created object. std::map::operator []()也确实返回引用,但是,如果没有给定键的对象,它将在映射内创建一个对象,并返回对该新创建对象的引用。 In order to create the object std::map must call the default constructor (a constructor with no additional arguments). 为了创建对象std::map必须调用默认构造函数(没有附加参数的构造函数)。

That is the reason why you code wont compile: Your class MyRec is not default constructable, but std::map::operator [] requires this. 这就是您的代码无法编译的原因:您的类MyRec不是默认可构造的,但是std::map::operator []需要此代码。


Thus you have three options: 因此,您有三个选择:

  1. Use std::map::insert() 使用std::map::insert()
  2. Use std::map::emplace() 使用std::map::emplace()
  3. Make MyRec default constructable. 使MyRec默认可构造。

In your code, you mention that you expect the [] operator to work the same as: 在您的代码中,您提到希望[] operator的工作方式与以下相同:

    (*((recMap.insert(std::make_pair(key,rec))).first)).second;

But it is not the same as that statement; 但这和那句话一样。 rather it's the same as: 而是和:

    (*((recMap.insert(std::make_pair(key,MyRec()))).first)).second;

Written like this, hopefully it's easier to see why the code doesn't compile (that is, MyRec does not define a parameter-less constructor ). 如此编写,希望可以更容易地了解为什么代码无法编译(即MyRec没有定义无参数的构造函数 )。

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