[英]How to add and print items in Linked List c
My main is: 我的主要是:
void main()
{
int flag = 1;
LinkedList *list = NULL;
list = makeList();
while (flag) {
add_last(list, makeNode(nextKey(), "uninitialized"));
printf("please enter 0 to stop any other number to go on \n");
scanf("%d",&flag);
}
printKeys(list);
}
I have 2 structs that define node and list: 我有2个定义节点和列表的结构:
typedef struct item{
int data;
char *charData;
struct item *next;
}item;
typedef struct{
struct item *head;
}LinkedList;
I create the list by the function: 我通过函数创建列表:
LinkedList *makeList(){
LinkedList *head = (LinkedList*)malloc(sizeof(LinkedList));
return head;
}
and the node by the function: 和节点的功能:
item *makeNode(int key, char* data){
item *newItem = (item*)malloc(sizeof(item));
if (newItem != NULL) {
newItem->data = key;
newItem->next = NULL;
}
return newItem;
}
Now I need to write 2 functions, 1 to add the new item in the end of the list, and the second to Print the list. 现在,我需要编写2个函数,其中1个用于在列表末尾添加新项,第二个用于打印列表。
The signing my first function is: 我的第一个功能签名是:
void add_last(LinkedList *list, item *newItem){
}
and the second is: 第二个是:
void printKeys(LinkedList *list){
}
I am novice in the world of "C" and I don't know how can I do this. 我是“ C”领域的新手,我不知道该怎么做。 I don't understand how to have access to the list. 我不知道如何访问该列表。
Thank... 谢谢...
The printKeys
function should iterate over the nodes until one node is found where next
is null
. printKeys
函数应该在节点上进行迭代,直到找到一个节点,其中next
为null
为止。 By doing so, the key
field should be printed. 这样,应该打印key
段。 The add_last
function should perhaps iterate until the last node is found, and then set the next
field of the last node to newItem
. add_last
函数也许应该迭代直到找到最后一个节点,然后将最后一个节点的next
字段设置为newItem
。
void add_last(LinkedList *list, item *newItem){
item* ptrTemp = list->head;
if (list!=NULL) {
if (list->head == NULL) {
list->head = newItem;
return;
}
while (ptrTemp->next != NULL) {
ptrTemp = ptrTemp->next;
}
ptrTemp->next = newItem;
}
}
void printKeys(LinkedList *list){
item* ptrTemp = list->head;
while (ptrTemp->next != NULL) {
printf("%d",ptrTemp->data);
ptrTemp = ptrTemp->next;
}
printf("%d\n",ptrTemp->data);
}
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