[英]regex grep filter with string
I have text like these : 我有这样的文字:
div class="ls-icon ls-item " data-ctrdot="214752854"> div class =“ ls-icon ls-item” data-ctrdot =“ 214752854”>
div class="ls-icon ls-item " data-ctrdot="213523235"> div class =“ ls-icon ls-item” data-ctrdot =“ 213523235”>
div class="ls-icon ls-item " data-ctrdot="788746365"> div class =“ ls-icon ls-item” data-ctrdot =“ 788746365”>
div class="ls-icon ls-item " data-ctrdot="332532436"> div class =“ ls-icon ls-item” data-ctrdot =“ 332532436”>
and i want to export : 我想出口:
data-ctrdot="214752854"> 数据ctrdot = “214752854”>
data-ctrdot="213523235"> 数据ctrdot = “213523235”>
data-ctrdot="788746365"> 数据ctrdot = “788746365”>
data-ctrdot="332532436"> 数据ctrdot = “332532436”>
but i dont know why this 但我不知道为什么
grep -o 'data-ctrdot="\\w*' grep -o'data-ctrdot =“ \\ w *'
does not work . 不起作用。 Thanks 谢谢
If by does not work you mean it outputs this: 如果by 不起作用 , 则表示输出以下内容:
data-ctrdot="214752854
data-ctrdot="213523235
data-ctrdot="788746365
data-ctrdot="332532436
Instead of 代替
data-ctrdot="214752854">
data-ctrdot="213523235">
data-ctrdot="788746365">
data-ctrdot="332532436">
Then yes, it's broken. 然后是的,它坏了。 But perhaps you could just inject the last two characters into the grep expression? 但是也许您可以将最后两个字符注入grep表达式中?
grep -o 'data-ctrdot="\w*">'
data-ctrdot="214752854">
data-ctrdot="213523235">
data-ctrdot="788746365">
data-ctrdot="332532436">
您可以使用:
awk '/data-ctrdot=/{print $NF}' file
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