使用Javascript在弹出窗口中打开链接但弹出窗口应该在新窗口中

Question

I'm trying to send a popup window of specific dimensions which also centers in the screen.

Here is my source:

 <li>
   <a class="google" href="http://www.google.com/" target="_blank" onclick="return windowpop(this.href, 545, 433)">Test</a>
 </li>

And JAVASCRIPT IS:

function windowpop(url, width, height) {

    alert('hello');

    var leftPosition, topPosition;

    //Allow for borders.
    leftPosition = (window.screen.width / 2) - ((width / 2) + 10);

    //Allow for title and status bars.
    topPosition = (window.screen.height / 2) - ((height / 2) + 50);

    //Open the window.
    window.open(url, "Window2", "status=no,height=" + height + ",width=" + width + 
    ",resizable=yes,left=" + leftPosition + ",top=" + topPosition + ",screenX=" + 
    leftPosition + ",screenY=" + topPosition + 
    ",toolbar=no,menubar=no,scrollbars=no,location=no,directories=no");
}

In this the pop up is generated. But I need that alert message in new window.

Answer 1

But I need that alert message in new window.

Since you are opening the same page ( this.href ), before calling the alert function, check if the current window has a parent (ie if it is a pop-up window):

    if (window.opener) {
    {
      alert('hello');
    }

UPDATE:

You should extract out the alert('hello'); code from the windowpop function and put it directly in the <script> section so that the opened page will load it.

Like that:

    <script>
    if (window.opener) {
    {
      alert('hello');
      ...
    }
</script>