C++ 因子程序：输出给定因子的数量

Question

I am writing a simple program that finds the factors of a list of integers through Linux Redirection. I am almost done, but I am stuck on one part. Here is my program so far:

#include<iostream>
using namespace std;
int main()

{
int counter = 0;
int factor;
cin >> factor;

while (cin)
{
if (factor < 0)
break;
cout << "The factors of " << factor << " are " << endl;
for(int i=factor; i>=1; i--)
if (factor % i == 0)
  {
    counter++;
    cout << i << endl;
  }
cout << "There are " << " factors." << endl;
cout << endl;
cin >> factor;
}
return 0;
}

Now the problem I have is in the line " cout << "There are " << " factors." << endl; ". I'm not sure how to calculate the number of factors output by the program.

For example:

The factors of 7 are

1

7

There are 2 factors.

How would I go about calculating and outputting the "2" in this example.

Help is greatly appreciated.

Answer 1

Instead of

cout << "There are " << " factors." << endl;

use

cout << "There are " << counter << " factors." << endl;

If you do that, you have to move the line where you define counter .

Instead of it being the first line in main , it needs to be moved to be the first line in the while loop.