C ++程序未使用.get输出预期的结果

Question

My prototype program isn't outputting as expected. I want to store 'Y' within the string active , but it's storing NA instead.

#include <iostream>
#include <string>
#include <fstream>
using namespace std;

int main()
{
    ifstream inFile;
    char testChar;
    string active;
    inFile.open("test.dat");

    inFile.get(testChar);
    if (testChar = 'N')
    {
        inFile.get(testChar);
        if (testChar = 'A')
            active = "NA";
        else
            active = "N";
    }
    else
        active = "Y";
    cout << endl << active << endl << endl;

    system("pause");
    return 0;
}

My textfile(text.dat) is just

Y

My expected output is Y

Actual Output NA

Not sure why this is happening

Answer 1

It's important to understand the difference between assignment ( = ) and testing for equality ( == ).

Change:

if (testChar = 'a')

To

if (testChar == 'a')

And similarly for the other cases.

Note that if you had compiled with warnings enabled the compiler would have reported these simple mistakes.