如何使其不显示少于x个字符的点？

Question

if less than x don't show a "..."

<?php echo substr(stripslashes($row['news_title']), 0, 20). ".."; ?>

I have it to show more than x if more than 20, but it shows "..." when there's 10 chars. Is there anyway I could have it not to show?

any tutorials?

Thanks!

Answer 1

Try like

<?php echo substr(stripslashes($row['news_title']), 0, 20);
      if(strlen($row['news_title']) > 20)
          echo ".."; 
?>

Answer 2

You could use CSS tricks , but this would be the code for doing it server-side:

if (strlen($row['news_title']) <= 20) {
    echo htmlspecialchars($row['news_title']);
} else {
    echo htmlspecialchars(substr($row['news_title'], 0, 20)), '...';
}

Note that strlen() counts bytes and not characters per se; this is important when you start working with Unicode, in which case you may want to consider using mb_strlen() .

Btw, using stripslashes() is somewhat of a red flag; if your quotes come out as escaped, the problem lies somewhere else and shouldn't be a problem of the presentation layer ... in fact, you should be using htmlspecialchars() instead.

Answer 3

这样就可以了。

<?php echo strlen(stripslashes($row['news_title']))>20 ?substr(stripslashes($row['news_title']), 0, 20)."...":stripslashes($row['news_title']); ?>

Answer 4

尝试编写自己的子字符串函数：它可能像这样http://www.sranko.com/nwP3LFit