[英]How can I make my output say Type and not Types if show_count is less than 2 in wordpress
So I'm using wp_list_categories
to output a set of lists and show_count
is equal to true
so I can see the amount of posts in that category. 所以我正在使用wp_list_categories
输出一组列表,而show_count
等于true
这样我就可以看到该类别中的帖子数量。
Anyways, I managed to use this code in my functions.php and remove the parenthesis around my post counts, wrap it with a span and have it say "Types"
after the number. 无论如何,我设法在我的functions.php中使用了这段代码,并删除了我的帖子计数中的括号,将其用一个跨距包裹起来,并在数字后加上"Types"
。
The problem is that if I have only 1 post assigned to that category it shouldn't be plural and say "Types"
. 问题是,如果我只给该类别分配了1个帖子,则不应为复数形式并说"Types"
。 If it equals less than 2 it should say "Type"
. 如果它小于2,则应说"Type"
。
Here is my code that I use in my functions.php for that: 这是我在functions.php中使用的代码:
/**
* filter the wp_list_categories and wrap with <span>
*/
add_action('pre_get_posts', 'mr_modify_archive_taxonomy_query');
$links = add_filter('wp_list_categories', 'cat_count_span');
function cat_count_span($links) {
$links = str_replace('</a> (', '</a> <span class="pull-right">', $links);
$links = str_replace(')', ' Types</span>', $links);
return $links;
}
I just need to add a conditional in there somehow that defines the show_count
and have it say: 我只需要在其中添加一个条件即可定义show_count
,并说:
if it equals less than 2 echo "Type" else echo "Types"
. if it equals less than 2 echo "Type" else echo "Types"
。
Just having a really hard time giving it this conditional. 给这个条件一个非常困难的时期。
not sure of the structure of $links but you could use count()
if its an indexed array to get the number of links eg 不确定$ links的结构,但是可以使用count()
如果它是一个索引数组来获取链接数,例如
add_filter('wp_list_categories', 'cat_count_span');
function cat_count_span($links) {
$needle ="<li"; // e.g. <li> <a etc.
$count= substr_count($links, $needle);
$word= 'Types';
if($count==1) $word= 'Type';
$links = str_replace('</a> (', '</a> <span class="pull-right">', $links);
$links = str_replace(')', $word.'</span>', $links);
return $links;
}
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