字符串串联和@

Question

I have the following code which uses a string like this :

string str = @"this is very important string ,which uses hardcoded name";

I want to change it to have a value of input argument

public void func (string name)
{
    // some code
    string str = "this is very important string ,which uses " + name;
}

When I generate the string I still need to use "@" what can I do?

string str = @("this is very important string ,which uses " + name);

Answer 1

You use @ before every string literal (and only literals, not variables) if you want to treat escape sequences literally. So in your case, you only need to do:

string str = @"this is very important string ,which uses " + name;

BTW, using @ for "this is very important string ,which uses " won't make a difference as it doesn't have any escape sequences.

More about verbatim string literals on MSDN :

A verbatim string literal consists of an @ character followed by a double-quote character, zero or more characters, and a closing double-quote character. A simple example is @"hello". In a verbatim string literal, the characters between the delimiters are interpreted verbatim, the only exception being a quote-escape-sequence. In particular, simple escape sequences and hexadecimal and Unicode escape sequences are not processed in verbatim string literals. A verbatim string literal may span multiple lines.

Thus an example where @ makes a difference may be for the tab character \\t :

string c = "hello \t world";    // hello     world <-- tab here
string d = @"hello \t world";   // hello \t world <-- treated literally