如何用1-1000的整数创建几乎排序的100数组？

Question

Part of my assignment requires 3 array of input size 100 with integers from 1-1000. Where 1st array is of random numbers from 1-1000. 2nd is sorted array from integers 1-1000. 3rd is almost sorted array from integers 1-1000.

My random array..

  int array [] = new int [100];    // Random Array of 100 
    for ( int i = 0 ; i < array-1 ; i++) {
      array [i] = (int) (Math.random () * 100);
     }

My sorted array..

  int [] array = new int[100];                    // Sorted Array of 100
    for (int a = 0; a < array.length; a++) {
      array[a] = (a + 1) * 10;
    }

But how to do a almost sorted array. I thought about shuffling but that will just be all random.

Answer 1

A faster solution:

int [] array = new int[100];    // Almost sorted Array of 100

array[0] = (int)(Math.random () * 10) + 1;

for (int a = 1; a < array.length; a++) {
  array[a] = array[a-1] + (int)(Math.random() * 12) - 2;
}

Hope that's close enough to an "almost sorted" array.

Answer 2

Try this,

        int[] values = new int[100];
        Random random = new Random();
        random.nextInt();
        for (int i = 0; i < 100; i++)
        {
            values[i] = random.nextInt(900) + 100;
        }

        Arrays.sort(values);
        for (int i = 0; i < 100; i++)
        {
            System.out.println(values[i]);
        }