使用相同类别的两个线程（偶数和奇数）打印1-1000

Question

So my task is this:

1. Instantiate two object of the same class

2. Provide a constructor argument, to designate a thread as even and another as odd .

3. Start both threads right one after other

4. Odd thread prints odd numbers from 0 to 1000

5. Even thread prints even numbers from 0 to 1000

6. However they should be in sync the prints should be 1 , 2 , 3 , 4 .....

7. One number on each line

However I can't seem to get the locks to release correctly. I've tried reading some of the similar problems on here but they all use multiple classes. What am I doing wrong?

Edit: My main class is doing this -

NumberPrinter oddPrinter = new NumberPrinter("odd");
NumberPrinter evenPrinter = new NumberPrinter("even");

oddPrinter.start();
evenPrinter.start();

and my output is - odd: 1 even: 2 ...

public class NumberPrinter extends Thread {

private String name;
private int starterInt;
private boolean toggle;


public NumberPrinter(String name) {
    super.setName(name);
    this.name=name;

    if(name.equals("odd")) {
        starterInt=1;
        toggle = true;

    }
    else if(name.equals("even")) {
        starterInt=2;
        toggle = false;
    }
}

@Override
public synchronized void run() {

    int localInt = starterInt;
    boolean localToggle = toggle;

    if(name.equals("odd")) {


    while(localInt<1000) {

        while(localToggle == false)
        try {
            wait();
        }catch(InterruptedException e) {

              System.out.println("Main thread Interrupted");

        }
    System.out.println(name+": "+localInt);
    localInt +=2;
    localToggle = false;
    notify();

       }
    }

    else {

        while(localInt<1000) {


            while(localToggle == true)
                try {
                    wait();
                }catch(InterruptedException e) {

                      System.out.println("Main thread Interrupted");

                }
            System.out.println(name+": "+localInt);
            localInt +=2;
            localToggle = true;
            notify();
    }
}
}
}

Answer 1

The key problem here is that the two threads have no way to coordinate with each other. When you have a local variable ( localToggle in this case) nothing outside the method can observe or alter its value.

If you share one object with both threads, however, its state can change, and if used correctly, those state changes will be visible to both threads.

You will see examples where the shared object is an AtomicInteger , but when you use synchronized , wait() and notify() , you don't need the extra concurrency overhead built into the atomic wrappers.

Here's a simple outline:

class Main {
  public static main(String... args) {
    Main state = new Main();
    new Thread(new Counter(state, false)).start();
    new Thread(new Counter(state, true)).start();
  }
  int counter;
  private static class Counter implements Runnable {
    private final Main state;
    private final boolean even;
    Counter(Main state, boolean even) {
      this.state = state;
      this.even = even;
    }
    @Override
    public void run() {
      synchronized(state) {
        /* Here, use wait and notify to read and update state.counter 
         * appropriately according to the "even" flag.
         */
      }
    }
  }
}

I'm not clear whether using wait() and notify() yourself is part of the assignment, but an alternative to this outline would be to use something like a BlockingQueue to pass a token back and forth between the two threads. The (error-prone) condition monitoring would be built into the queue, cleaning up your code and making mistakes less likely.

Answer 2

I finally got it working in a way that meets the standards required by my assignment. Thank you all for your input. I'll leave the answer here for anyone who might need it.

public class Demo {

public static void main(String[] args) {

    NumberPrinter oddPrinter = new NumberPrinter("odd");
    NumberPrinter evenPrinter = new NumberPrinter("even");



    oddPrinter.start();
    evenPrinter.start();




    System.out.println("Calling thread Done");

}

public class NumberPrinter extends Thread {

private int max = 1000;
static Object lock = new Object();
String name;
int remainder;
static int startNumber=1;



public NumberPrinter(String name) {

        this.name = name;

        if(name.equals("even")) {
            remainder=0;

        }else {
            remainder=1;


        }
    }

@Override
public void run() {



        while(startNumber<max) {
            synchronized(lock) {
                while(startNumber%2 !=remainder) {
                    try {
                    lock.wait();
                    }catch(InterruptedException e) {
                        e.printStackTrace();
                    }
                }
                System.out.println(name+": "+startNumber);
                startNumber++;
                lock.notifyAll();
            }
        }

}

}