需要一个正则表达式来使用Java提取字符串的一部分

Question

I need a regex to extract the a portion of a string after 'n' occurrences of a particular character

For example the string is : "aa/bb/cc/dd/ee/ff/gg/hh/ii/jj/kk/ll/mm/nn/oo/pp" I need the content aa/bb/cc/dd/ee/ff

The followed the below approach but couldn't get the match. Please suggest i am wrong below

matcher = Pattern.compile("((?:[^/]*/){5})").matcher(regExString);
if (matcher.matches()) {
String str = matcher.group(1);
System.out.println(str);
}

Answer 1

try this

    if (matcher.find()) {
        String str = matcher.group(1);
        System.out.println(str);
    }