如何从字符串元组列表中检索元组

Question

a=['(10,13)', '(23,45)', '(56,78)']

Here each item in list a is a string

I want an other list like this:

b=[(10,13),(23,45),(56,78)]

where each item is a tuple and each element in each tuple is an integer.

Answer 1

Use ast.literal_eval and a list comprehension :

>>> from ast import literal_eval
>>> a = ['(10,13)', '(23,45)', '(56,78)']
>>> b = [literal_eval(x) for x in a]
>>> b
[(10, 13), (23, 45), (56, 78)]
>>>

Answer 2

You can use ast.literal_eval .

>>> from ast import literal_eval
>>> a = ['(10,13)', '(23,45)', '(56,78)']
>>> b = [literal_eval(s) for s in a]
>>> b
[(10, 13), (23, 45), (56, 78)]

Answer 3

You can also use map:

from ast import literal_eval
a=['(10,13)', '(23,45)', '(56,78)']
b=map(literal_eval,a)  #[(10, 13), (23, 45), (56, 78)]