如何将字符串解析为元组列表

Question

I have a string of the format -

" ( (4, 4), (11, 23), (8, 2), (12, 4), (7, 9) ) "

What is the best way in which I will get this string into meaningful integer tuples? Lets say fun(s) is a function which takes such string s as parameter and returns list of tuple a

Ex.

a = fun("( (2, 3), (1, 4) )")
print (a)
>>> [(2, 3), (1, 4)]
a[0]
>>> (2, 3)
a[0][1]
>>> 3

Answer 1

For this kind of thing, ast.literal_eval is preferred to just the built-in eval , especially if the string is something that may come from an unknown source. The call interface is the same as eval :

print(list(ast.literal_eval(s)))

However, ast.literal_eval will guard against code insertions that may call system services (such as those that might delete files, etc.), and only accept literal values.

Answer 2

You can use Python's built-in eval() function.

In this case, you can write your code like this:

s = " ( (4, 4), (11, 23), (8, 2), (12, 4), (7, 9) ) "
print(list(eval(s)))