为什么赋值运算符重载中不需要get函数？

Question

I am just curious as to why this is. Is it simply the magical quality of the overload's definition being inside the class that both objects are made from? I was thinking about it and it felt just slightly strange to me that one function has access to member data of two objects.

myClass& myClass::operator= (const myClass& a){
    // shallow copy
    arraySize = a.arraySize; // no get functions needed

    // deep copy
    theArray = new int[arraySize];    // no get functions needed
    for (int i = 0; i < arraySize; i++){
        theArray[i] = a.theArray[i];
    }
}

Answer 1

访问权限是基于类的，您在成员函数中使用的对象不会限制您的访问。

Answer 2

myClass can access members of myClass. Access isn't based on the instance, it's based on the class.