如果ip为4个八位字节，为什么in_addr中的s_addr是无符号长而不是无符号长？
[英]Why is s_addr within in_addr an unsigned long instead of a mere unsigned if ip's are 4 octets?
问题描述
Is it for ipv6? 
是ipv6吗？ If ipv4 is s_addr just the dotted quad reinterpreted as a 32 bit integer? 如果ipv4是s_addr，那么只是将虚线四边形重新解释为32位整数？
1 个解决方案
解决方案1
3 已采纳 2014-04-17 14:23:53
unsgined long guarantees that the size of the variable is at least 4 bytes, thus holding the entire ip. unsgined long保证变量的大小至少为4个字节，从而保存整个ip。 An unsigned int can be smaller. unsigned int可以更小。
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