Bash shell脚本：如何替换特定字节偏移处的字符

Question

I'm looking to replace characters at specific byte offsets.

Here's what is provided: An input file that is simple ASCII text. An array within a Bash shell script, each element of the array is a numerical byte-offset value.

The goal: Take the input file, and at each of the byte-offsets, replace the character there with an asterisk.

So essentially the idea I have in mind is to somehow go through the file, byte-by-byte, and if the current byte-offset being read is a match for an element value from the array of offsets, then replace that byte with an asterisk.

This post seems to indicate that the dd command would be a good candidate for this action, but I can't understand how to perform the replacement multiple times on the input file.

Input file looks like this:

00000
00000
00000

The array of offsets looks this:

offsetsArray=("2" "8" "9" "15")

The output file's desired format looks like this:

0*000
0**00
00*00

Any help you could provide is most appreciated. Thank you!

Answer 1

Please check my comment about about newline offset. Assuming this is correct (note I have changed your offset array), then I think this should work for you:

#!/bin/bash

read -r -d ''
offsetsArray=("2" "8" "9" "15")
txt="${REPLY}"
for i in "${offsetsArray[@]}"; do
    txt="${txt:0:$i-1}*${txt:$i}"
done
printf "%s" "$txt"

Explanation:

• read -d '' reads the whole input (redirected file) in one go into the $REPLY variable. If you have large files, this can run you out of memory.
• We then loop through the offsets array, one element at a time. We use each index i to grab i-1 characters from the beginning of the string, then insert a * character, then add the remaining bytes from offset i . This is done with bash parameter expansion . Note that while your offsets are one-based, bash strings use zero-based indexing.

In use:

$ ./replacechars.sh < input.txt
0*000
0**00
00*00
$ 

Caveat:

This is not really a very efficient solution, as it causes the sting containing the whole file to be copied for every offset. If you have large files and/or a large number of offsets, then this will run slowly. If you need something faster, then another language that allows modification of individual characters in a string would be much better.

Answer 2

The usage of dd can be a bit confusing at the time, but it's not that hard:

outfile="test.txt"

# create some test data
echo -n 0123456789abcde > "$outfile"

offsetsArray=("2" "7" "8" "13")
for offset in "${offsetsArray[@]}"; do
    dd bs=1 count=1 seek="$offset" conv=notrunc of="$outfile" <<< '*'
done

cat "$outfile"

Important for this example is to use conv=notrunc , otherwise dd truncates the file to the length of blocks it seeks over. bs=1 specifies that you want to work with blocks of size 1, and seek specifies the offset to satart writing count blocks to.

The above produces 01*3456**9abc*e

Answer 3

With the same offset considerations as @DigitalTrauma's superior solution, here's a GNU awk-based alternative. This assumes your file contains no null bytes

(IFS=','; awk -F '' -v RS=$'\0' -v OFS=''  -v offsets="${offsetsArray[*]}" \
'BEGIN{split(offsets, o, ",")};{for (k in o)  $o[k]="*"; print}' file)

0*000
0**00
00*00