如何在C中的数组中替换特定但不断变化的一系列字符？

Question

I am working on 2 different programs, but have the same problem for both. I have a char array (that doesn't hold meaningful text) that I use for drawing things on the screen. The first one is for a race line that shows progress, and the other one for the map of an area that can be modified.
What I want to do is overwrite a section of the array, not the entire array, without changing the array's size. For example, if array1 looks like |..........| and I wanted to add a fallen tree at position 3 and a rock at position 10 it would change to |..-->>>..@| . What I meant in my title for 'specific' is that the amount of characters to be replaced is given by me or determined during execution, instead of calling a function that automatically knows when to stop.
I thought of doing it with a for loop, like:

char tree[5] = "-->>>";
char map[12] = "|..........|";
int offset = 3; //position from which to start replacing characters
object_size = sizeof(tree) / sizeof(char); //to get the length of the object to be added
for (int i = 0; i < object_size; i++) {
    map[offset + i] = tree[i];
}  

Is there a cleaner way to do it? I'm sure there must already be a function that does it, but most of what I find is in other languages. The idea is to then be able to use a 2-dimensional array to store the map and modify bigger areas.

Answer 1

If I have correctly understood, you do not want to copy the terminating null. The standard library function to use is void *memcpy(void *dest, void *src, size_t size) that copies exactly size bytes from src to dest .

But you have to ensure that there is enough room at dest to accept the size bytes

Answer 2

You can take a look at

https://www.tutorialspoint.com/c_standard_library/string_h.htm

And for you,

char *strcpy(char *dest, const char *src)

char *strncpy(char *dest, const char *src, size_t n)

They can make your code cleaner, but i think that deep inside, they do what you're doing manually.