[英]Can the arguments for CUDA kernel launch be dynamic?
i want to pass a random no. 我想随机通过。 to the threads, like
到线程,像
main()
{
.
.
.
func<<<1,10>>(rand()%10);
.
.
.
}
is it possible to do that? 有可能这样做吗?
i am quite new to CUDA programming and I might have missed a crucial point here. 我对CUDA编程很陌生,我可能错过了关键点。 Please help.
请帮忙。 Thanks in advance.
提前致谢。
Yes, it's possible. 是的,有可能。
(Note: your kernel call syntax isn't quite right: func<<<1,10>>
, but I assume that's a typing error) (注意:您的内核调用语法不太正确:
func<<<1,10>>
,但是我认为这是键入错误)
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