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CUDA内核启动的参数可以动态吗?

[英]Can the arguments for CUDA kernel launch be dynamic?

i want to pass a random no. 我想随机通过。 to the threads, like 到线程,像

main()
{
.
.
.

func<<<1,10>>(rand()%10);
.
.
.
}

is it possible to do that? 有可能这样做吗?

i am quite new to CUDA programming and I might have missed a crucial point here. 我对CUDA编程很陌生,我可能错过了关键点。 Please help. 请帮忙。 Thanks in advance. 提前致谢。

Yes, it's possible. 是的,有可能。

(Note: your kernel call syntax isn't quite right: func<<<1,10>> , but I assume that's a typing error) (注意:您的内核调用语法不太正确: func<<<1,10>> ,但是我认为这是键入错误)

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