[英]Getting values of items in IList?
Is there any way to get the values of items in the IList? 有没有办法获取IList中的项的值? It goes like this: 它是这样的:
Assume we have an IList list
and a method private IList getValues(int ID)
假设我们有一个IList list
和一个方法private IList getValues(int ID)
then we initialize IList list
like: 然后我们初始化IList list
如:
IList list = getValues(SelectedID)
After the processing, IList list
now contains 2 elements, each with it's own collection: 在处理之后, IList list
现在包含2个元素,每个元素都有自己的集合:
[0]
{
GroupName = "test01"
GroupID = 1
}
[1]
{
GroupName = "test02"
GroupID = 2
}
How will I get the GroupName of the first element? 我如何获得第一个元素的GroupName? I can't just call it like list[0].GroupName
, can I? 我不能把它称为list[0].GroupName
,我可以吗?
If you know the type of the object, you can use this to get what you want. 如果您知道对象的类型,则可以使用它来获得所需的内容。
list.Cast<Group>().ElementAt(0).GroupName
Group as in your object name. 在对象名称中分组。
Try the following, you need to create a list with your custom object. 请尝试以下操作,您需要使用自定义对象创建一个列表。 I created a dummy class here named CustomClass, and creating a list with the known type. 我在这里创建了一个名为CustomClass的虚拟类,并创建了一个已知类型的列表。
public class CustomClass
{
public string GroupName { get; set; }
public int GroupID { get; set; }
}
protected void Page_Load(object sender, EventArgs e)
{
List<CustomClass> list = new List<CustomClass>();
foreach (var x in list) {
Console.WriteLine(x.GroupName);
}
}
You can use FindIndex method, example 您可以使用FindIndex方法,例如
class MyClass2
{
public string Name { get; set; }
public int Age { get; set; }
public int Type { get; set; }
}
List<MyClass2> myLists = new List<MyClass2>();
myLists.Add(new MyClass2() { Age = 1, Name = "Mast", Type = 560 });
myLists.Add(new MyClass2() { Age = 2, Name = "Oli", Type = 778 });
myLists.Add(new MyClass2() { Age = 3, Name = "AS", Type = 9458 });
myLists.Add(new MyClass2() { Age = 4, Name = "ABC", Type = 100 });
int result1 = myLists.FindIndex(T => T.Type == 9458); //2
int result2 = myLists.FindIndex(T => T.Name == "Oli"); //1
please refer http://msdn.microsoft.com/en-us/library/x1xzf2ca.aspx 请参阅http://msdn.microsoft.com/en-us/library/x1xzf2ca.aspx
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