将文件名与路径分开

Question

I have a file whose path is like this : D:\\Documents and Settings\\user\\Desktop\\Folder\\File1.txt. Here File1.txt is file name. Now I want to separate this file name from the file path. If I have,

path = C:\\Documents and Settings\\user\\Desktop\\Folder\\File1.txt

then I want to store this name of the file in to filename . so output will look like this : filename=File1.txt I am not getting any idea about this. I am new in python..can anybody help me please in python...???

Answer 1

use os module

import os 
fileName = os.path.basename(path)

Answer 2

If you have already have pathname, just split it and extract the filename from it

path = "C:\\Documents and Settings\\user\\Desktop\\Folder\\File1.txt"
temp=path.split('\\')
filename=temp[-1]
print filename

Answer 3

If you want file name without knowing what os is ,

try this ,

>>> import ntpath
>>> ntpath.basename("C:\Documents and Settings\user\Desktop\Folder\File1.txt")
'File1.txt'
>>> ntpath.basename("/etc/apache-perl/httpd.conf")
'httpd.conf'