[英]How to pass numpy array inside of struct to ctypes function?
I'm trying to wrap some third-party code from a library in my Python application.我正在尝试从我的 Python 应用程序中的库中包装一些第三方代码。 Essentially, the function I would like to call takes a struct as input that houses (among other things) pointers to double arrays.本质上,我想调用的函数将一个结构作为输入,其中包含(除其他外)指向双数组的指针。 A simplified example would be:一个简化的例子是:
myfunc.h: myfunc.h:
typedef struct mystruct_t {
int n;
double *x;
} mystruct_t;
double myfunc(mystruct_t* data);
myfunc.c : myfunc.c :
#include "myfunc.h"
double myfunc(mystruct_t* data) {
double result = 0.;
for(int i = 0; i < data->n; i++) {
result += data->x[i];
}
return result;
}
Makefile :生成文件:
CC = gcc
CFLAGS = -g -Wall -fPIC -lm -std=gnu99
all: libmyfunc.so
m.PHONY : clean
libmyfunc.so: myfunc.o
gcc -shared -Wl,-soname,$@ -o $@ $^
%.o: %.c
$(CC) -c $(CFLAGS) $<
clean:
rm -vf libmyfunc.so *.o
I would like to wrap myfunc
using NumPy, ctypes.Structure
and numpy.ctypeslib
so that I can pass NumPy arrays to myfunc
as attributes of mystruct_t
.我想使用 NumPy、 ctypes.Structure
和numpy.ctypeslib
包装myfunc
,以便我可以将 NumPy 数组作为mystruct_t
属性传递给myfunc
。 So far I've been trying the following:到目前为止,我一直在尝试以下方法:
myfunc.py: myfunc.py:
#!/usr/bin/env python
import numpy as np
import numpy.ctypeslib as npct
import ctypes
import os
array_1d_double = npct.ndpointer(dtype=np.double, ndim=1, flags='C_CONTIGUOUS')
class MyStruct(ctypes.Structure):
_fields_ = [
('n', ctypes.c_int16),
('x', array_1d_double)
]
libmyfunc = npct.load_library('libmyfunc', os.path.dirname(__file__))
libmyfunc.myfunc.restype = ctypes.c_double
libmyfunc.myfunc.argtypes = [
ctypes.POINTER(MyStruct)
]
x = np.array([1.0, 2.0, 3.0, 4.0])
mystruct = MyStruct()
mystruct.n = len(x)
mystruct.x = x
res = libmyfunc.myfunc(mystruct)
However, this fails with the following error message:但是,这失败并显示以下错误消息:
$ python myfunc.py
Traceback (most recent call last):
File "./myfunc.py", line 26, in <module>
mystruct.x = x
TypeError: cannot be converted to pointer
How do I define my function signatures correctly so that type conversion can happen?如何正确定义函数签名以便进行类型转换? Or do I need to convert x
somehow before assigning it to mystruct.x
?或者我是否需要在将x
分配给mystruct.x
之前以某种方式转换它?
Unfortunately I cannot change the signature of the method I would like to call and I would like to not have to write wrapper C code unless it is absolutely necessary.不幸的是,我无法更改要调用的方法的签名,并且除非绝对必要,否则我不想编写包装器 C 代码。 The other questions and resources that I've found on this only deal with either ctypes.Structure
s or numpy.ctypeslib
, but can you make them work together?我在这方面发现的其他问题和资源仅涉及ctypes.Structure
s 或numpy.ctypeslib
,但你能让它们一起工作吗?
I've uploaded my reduced example as a gist so you can use it as a starting point.我已经上传了我的简化示例作为要点,因此您可以将其用作起点。
Many thanks in advance!提前谢谢了!
You can remove array_1d_double
.您可以删除array_1d_double
。 It is not needed.不需要。
The struct should be declared like this:该结构应声明如下:
class MyStruct(ctypes.Structure):
_fields_ = [
('n', ctypes.c_int),
('x', ctypes.POINTER(ctypes.c_double))
]
I've changed both types.我已经改变了两种类型。 You had c_int16
, but the type you used in the C code is int
.您有c_int16
,但您在 C 代码中使用的类型是int
。 That maps to c_int
.那映射到c_int
。 And likewise for the array, that is double*
.同样对于数组,那是double*
。 In ctypes that is POINTER(ctypes.c_double)
.在 ctypes 中是POINTER(ctypes.c_double)
。
The struct should be initialised like this:该结构应该像这样初始化:
mystruct = MyStruct()
mystruct.n = len(x)
mystruct.x = npct.as_ctypes(x)
With these changes, your code works as intended.通过这些更改,您的代码可以按预期工作。
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