[英]Cant delete void pointer from vector in c++
hi everybody im trying to delete void pointer from vector, the program crash in the delete. 大家好,我试图从向量中删除空指针,程序在删除时崩溃。 thank you very much!
非常感谢你!
template <class T> class tArray_t : public vpArr_t {
virtual ~tArray_t() {
for (vector<void*>::iterator it = array.begin() ; it != array.end(); )
{
vector<void*>::iterator nextElement = it+1;
delete *it; // here is the crash
it = nextElement;
}
}; };
Deleting void
pointers is undefined . 删除
void
指针是未定义的 。 You are getting exactly what you have asked for. 您正在得到您所要求的。
Use vector<T*>
instead of vector<void*>
. 使用
vector<T*>
代替vector<void*>
。 If you eg have vector<void*>
inherited from your base class, you have to cast the pointer to T*
before deleting it. 例如,如果从基类继承了
vector<void*>
,则必须在删除T*
之前将其转换为T*
。
delete static_cast<T*>(*it);
You may also want to save you some work and use boost::ptr_vector
. 您可能还需要保存一些工作并使用
boost::ptr_vector
。
Compiler know how many bytes to be deleted with a typed pointer. 编译器知道要使用类型化的指针删除多少字节。 Think of it this way, a void * pointer doesn't have any information about the memory it pointing to, nobody knows how to delete a pointer like this.
这样想吧,void *指针没有有关它指向的内存的任何信息,没人知道如何删除这样的指针。 To the minimum, you don't know what size needs to be deleted, and no information about which destructor to call.
至少,您不知道需要删除什么大小,也没有有关调用哪个析构函数的信息。
Class A;
A * p = new A();
delete p;
When delete p is executed, compiler knows A destrcutor needs to be called, and the size of memory needs to be cleaned up is sizeof(A). 当执行delete p时,编译器知道需要调用一个析构函数,并且需要清除的内存大小为sizeof(A)。 A void * pointer is missing all this information.
无效*指针会丢失所有这些信息。
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