在ASP.Net中打开弹出页面后，如何返回上一个窗口页面？

Question

Is it possible to go back to previous window after opening a pop-up window page?

I have a page with a button, after a button is clicked a new pop-up window page appears. Inside that pop-up window has a button too and every time the user click that button it must go back to the previous window where it came from.

I used below vb.net code to open a pop-up window on button click

ScriptManager.RegisterClientScriptBlock(Me, GetType(String), "uniqueKey", "PopupWindow('PopUp.aspx','myPop','1000','700')", True)

where PopupWindow is a javascript function.

I don't know what code to use on going back to window page. I tried several javascript and vb.net codes but it's not working.

Please help.

Thanks in advance.

Answer 1

You can save it in viewstate/Session and navigate it on Page load

protected void Page_Load(object sender, EventArgs e)
 {
     if( !IsPostBack )
     {
        ViewState["RefUrl"] = Request.UrlReferrer.ToString();
     }
  }

and on close of popup

 object refUrl = ViewState["RefUrl"];
  if (refUrl != null)
      Response.Redirect((string)refUrl);

Also you can try in Javascript javascript:history.go(-1) and window.history.back()