如何检查一个弹出窗口页面是否已在asp.net中打开？

Question

I am using a javascript to open a pop-up window in asp.net. What I want to do is when the pop-up window is already open, it will just set the focus on it and refresh the pop-up window rather than opening a new pop-up window. Else when it is close, that's the time that the pop-up window must open.

I tried below codes but didn't work..

var winPop = false; 
function PopupCenter(pageURL, title,w,h) 
 { 
   if(winPop && !winPop.closed)
   {  
     winPop.focus();  
   }  
   else
   {  
     var left = (screen.width/2)-(w/2);
     var top = (screen.height/2)-(h/2);
     winPop = window.open(pageURL, title, 'toolbar=no, location=no, directories=no, status=no, menubar=no, scrollbars=no, resizable=no, copyhistory=no, width='+w+', height='+h+', top='+top+', left='+left);
     winPop.focus();     
   }  

} 

Thanks in advance.

Answer 1

You can use window.location.indexOf and by using that you can check that window is opened or not from its url

and another solution as per your code is that make that variable null when your window is going to close and then check that variable is null or not when it is null open new window else set focus.

Good Luck!

-> code in Parent window put this whole code in parent window like

var w= null;

then set variable like w= window.open();

then check that if (w!= null) then open new window else do nothing

-> Code in Popup window and also be careful to set w= null in popup window

$( window ).unload(function() { w=null; });

when child window is going to close.