gcc中的编译器优化

Question

I have a code in C and I am running some tests. I need to access an array, but in "read-only" mode. I am doing something like this:

for (int i= 0; i < 1000; i++){
    int a = shared_array[rand() % 64];
    int b = shared_array[rand() % 64];
}

My question is: How can I fetch a value from memory and be sure that the compiler is not optimizing it by removing these instructions, given that in my test I am doing nothing with those values. Even if I add an operation int v = a + b , again v is not used anywhere else, so it could be ignored.

I am using gcc with -O3, and I need to do it that way to be able to compare it against results from another source.

Answer 1

The typical way you force the compiler to actually read an otherwise unused variable is to make it volatile . This should guarantee the compiler actually read/write the variable from RAM when it is used.

Answer 2

在当前编译单元（源文件）中未定义的函数中使用a和b 。

Answer 3

The keyword volatile tells the compiler to not optimize that code. This applies for both variables and functions. You can even do this on inline assembly, which is a more advanced topic. See this question .

It is usually applied after the type specifier, eg int volatile i = 0; .