Sed Command替换如何将一个或多个空格视为一个？

Question

I use this command to insert a line. If there is a space in the pattern between two entries in the text or file it prints the content on the new line. It works fine, however sometimes I encounter 2 spaces or 3 spaces instead of one that I'm looking for in the pattern so I get additional blank lines.

sed "s/ /\n/g"

I want to print a new line only the sed finds something in the pattern. How should I use the sed command to treat 1 space or double or triple spaces as one substitute?

Answer 1

You need a quantifier:

sed "s/  */\n/g"

or

sed 's/ \+/\n/g'       # With GNU sed

or

sed -r 's/ +/\n/g'

or

sed 's/ \{1,\}/\n/g'

or

sed -r 's/ {1,}/\n/g'

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If using BSD sed,

sed 's/  */\'$'\n''/g'

or

sed -r 's/ +/\'$'\n''/g'

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You could also use tr :

tr -s ' ' '\n'

The -s option squeezes repeats of a character in set1, ie the ' ' in this example.

Answer 2

I would do something like...

sed -e 's/\s\+/\n/g' [filename]

To find and replace one or more white space with a new line.