如何将带有空格的参数传递给sed命令？

Question

I have the below function in my shell script

fnChangeTxt()
{
        sed -i 's/<div id="'$1'"><p>*.*</<div id="'$1'"><p>'$2'</' /var/www/html/alarm.html
}

I would like use the below the pass a string to the sed command via $2 argument.

fnChangeTxt 'demo' 'This text to sed'

Hoever this doesn't work and produces and error, I assume it is due to the white spaces as the below command works fine.

fnChangeTxt 'demo' 'This_text_to_sed'

Is there a way to do this with spaces?

Thanks in advance.

Answer 1

将参数（ $1等）括在双引号中，以防止它们被单词分割（并防止其他可能不愉快的额外解析）：

sed -i "s/<div id=\"$1\"><p>*.*</<div id=\"$1\"><p>$2</" /var/www/html/alarm.html

Answer 2

尝试使用转义字符：

fnChangeTxt 'demo' 'This\ text\ to\ sed'