[英]why does printf(“-%d”,025); print -21? (C)
This might be really simple, but i was wondering why if you have this code it prints out -21? 这可能非常简单,但我想知道为什么如果你有这个代码它打印出-21?
#include <stdio.h>
main() {
printf("-%d",025);
}
025 is octal == 2 * 8 + 5 == 21 decimal 025是八进制== 2 * 8 + 5 == 21十进制
You have a minus sign in front of your integer format string placeholder, therefore it prints -21 在整数格式字符串占位符前面有一个减号,因此它打印-21
Integer literals starting with 0
are in octal (base 8). 以
0
开头的整数文字是八进制(基数为8)。 So 025
is 2*8 + 5
= 21
. 所以
025
是2*8 + 5
= 21
。
If you use an editor with syntax highlighting it might show you this. 如果您使用带语法突出显示的编辑器,它可能会显示此信息。
Trivia: 0
itself is actually in octal for this reason, not decimal! 琐事:因为这个原因,
0
本身实际上是八进制,而不是十进制!
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