[英]Why does `printf(“%c”, 5)` print a vertical bar?
Here is the code 这是代码
#include <stdio.h>
int main()
{
printf ("\t%d\n",printf("MILAN"));
printf ("\t%c",printf("MILAN"));
}
Here is the output 这是输出
$gcc -o main *.c
$main
MILAN 5 米兰5
MILAN | 米兰|
Now the question is 现在的问题是
Why printf return | 为什么printf返回| when we are printing characters (formatter as %c) ? 当我们打印字符时(格式为%c)?
What is the relation between 5 and | 5和|之间的关系是什么? here? 这里?
Your question really boils down to the behaviour of printf("%c", 5);
您的问题实际上归结为printf("%c", 5);
的行为printf("%c", 5);
. 。
The actual output is a function of the character encoding used by your platform. 实际输出取决于平台使用的字符编码 。 If it's ASCII (very common) then it will output the control character ENQ
. 如果是ASCII(非常常见),则将输出控制字符 ENQ
。 What you actually get as an output will depend on your command shell, and a vertical bar is not an unreasonable choice. 您实际获得的输出将取决于命令外壳,竖线也不是不合理的选择。
printf
returns the number of characters printed . printf
返回打印的字符数 。 In this case, that number is 5, as you've seen. 如您所见,在这种情况下,该数字为5。 The second print you're doing tries to typecast that int
to a char
, which C lets you do because it's C. On your computer, it shows up as a |. 您正在执行的第二个打印尝试将int
转换为char
,因为C是C,所以C可以让您这样做。在计算机上,它显示为|。 I see it rendered as a blank character. 我看到它呈现为空白字符。 As @Bathsheba says, the integer 5
corresponds to a control character in ASCII, and the rendering for those is system-dependent. 正如@Bathsheba所说,整数5
对应于ASCII中的控制字符,并且这些字符的呈现方式与系统有关。
Here's an ascii table, if you're curious about other numbers . 如果您对其他数字感到好奇,这是一张ascii表 。
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