Python 3无法获取字母输入

Question

I am using Enthought Canopy compiler. I am trying to get a word input from user using this code below:

starting_day = str(input("Enter the day you will be leaving: "))

however whenever I test the var by running the program I keep getting the error below after assigning a string of letters to the variable(it's runs when I give it numbers)

Enter the day you will be leaving: monday

NameError                                 Traceback (most recent call last)

C:\Users\user\AppData\Local\Enthought\Canopy32\App\appdata\canopy-1.1.0.1371.win-x86\lib\site-packages\IPython\utils\py3compat.pyc in execfile(fname, glob, loc)
    174             else:

    175                 filename = fname

--> 176             exec compile(scripttext, filename, 'exec') in glob, loc

    177     else:

    178         def execfile(fname, *where):

c:\users\user\appdata\local\temp\tmpnwkfhu.py in <module>()

----> 1 starting_day = str(input("Enter the day you will be leaving: "))

      2 

      3 lenght_of_stay = int(input("Enter the number of days you will say for: "))

      4 

      5 print(starting_day, lenght_of_stay)

<string> in emulated_input(prompt)

<string> in <module>()

NameError: name 'monday' is not defined

Answer 1

You are running this with Python 2 , not Python 3.

In Python 2, input() passes all input to eval() ; the string monday is interpreted as a Python name, which throws a NameError because it is not defined.

You can see this in your traceback as well; exec in Python 3 is a function , in Python 2 it is a statement. The traceback uses it as a statement (no parenthesis). Most of all, you are using Enthought Canopy, which can only support Python 2 .

Either use raw_input() instead, or run your code with an actual Python 3 interpreter.