正则表达式匹配带括号的单词？

Question

I have problem with regular expressions. I have strings like this:

test(r), testtest(r,r), example, example2, exmp (r,5)

I would like to find all words without blanks between text and the parenthesis. From the string above, I want to get:

test(r), testtest(r,r)

I created this regexp but it catches only brackets with content inside:

/\(([^\)]+)\)/g

Thanks for all answers.

Edit: I am working in Ruby, and this regex works perfectly /\w+\(([^)]+)\)/g .

What should I do if I would like to separate words with commas between brackets and without? For example how do I get this?

testtest(r,r) <-with comma
test(r) <-without comma

Answer 1

You can add a \\w+ in front of the pattern:

/\w+\(([^)]+)\)/g

This will match one or more 'word' characters (which includes letters, digits, and underscores) followed by an ( , followed by one or more of any character other than ) , followed by a ) .

If you want to know want to be able to capture the word that appears before the parentheses separately, you can put it in a group like this:

/(\w+)\(([^)]+)\)/g

In your example, this would give group 1: test and group 2: r for the first match and group 1: testtest and group 2: r,r for the second match.

Answer 2

Recently had the same issue myself. Doing this solved my problem:

(\w+\([\w, ]+\))

Hope it helps!

Answer 3

像这样：

/\w+\(\w([,]\w)?\)/g

Answer 4

text = '''test(r), testtest(r,r), example, example2, exmp (r,5)'''
pattern = r'\w+\([^()]+\)'
m = re.compile(pattern)
results = m.finditer(text)
for r in results:
    print(r)