图像处理中的步幅和宽度

Question

I HAVE A 1bpp image that needs to be read. 我有一个需要读取的1bpp图像。

I came across the following logic. 我遇到了以下逻辑。 but I am not sure what it is trying to do. 但我不确定它要做什么。

     int value = (imagebmd.Width + 15) >> 3;       
     byte* row = (byte*)imagebmd.Scan0;

I don't understand what value is stored in columns and row variables. 我不明白列和行变量中存储了什么值。

Answer 1

int columns = (imagebmd.Width + 7) >> 3;

This is byte length of image line. 这是图像行的字节长度。 It is equivalent of rounding up 相当于四舍五入

columns = Ceil(bitwidth / 8)

row is pointer to image data start address. 行是指向图像数据起始地址的指针。