Java：使用正则表达式提取String中的各种值

Question

I want to write a function to extract various number of values from a String according to a regex pattern:

Here is my function code:

/**
 * Get substrings in a string using groups in regular expression.
 * 
 * @param str
 * @param regex
 * @return
 */
public static String[] regexMatch(String str, String regex) {
    String[] rtn = null;
    if (str != null && regex != null) {
        Pattern pat = Pattern.compile(regex);
        Matcher matcher = pat.matcher(str);
        if (matcher.find()) {
            int nGroup = matcher.groupCount();
            rtn = new String[nGroup];
            for (int i = 0; i < nGroup; i++) {
                rtn[i] = matcher.group(i);
            }
        }
    }
    return rtn;
}

When I test it using:

String str = "nets-(90000,5,4).dat";
String regex = "(\\d+),(\\d+),(\\d+)";
String[] rtn = regexMatch(str, regex);

I get:

rtn: [90000,5,4,90000,5]

How can I get rtn to be [90000,5,4] as I expected?

Answer 1

Your array currently store

[0] -> 90000,5,4
[1] -> 90000
[2] -> 5

That is why you are seeing as output [90000,5,4,90000,5] . It is because group(0) represents entire match so it returns 90000,5,4 .

What you need is match from groups 1, 2 and 3.

(\\d+),(\\d+),(\\d+)
   1      2      3

So change

rtn[i] = matcher.group(i);

to

rtn[i] = matcher.group(i+1);

Answer 2

First, I would start the for loop with 1 so you can get the grouping you are declaring in your regex. The loop should look like this:

for (int i = 1; i <= nGroup; i++) {
            rtn[i] = matcher.group(i);
        }

Group 0 is known to be the entire matching string for your regex. The grouping is from:

String regex = "(\\d+),(\\d+),(\\d+)";

You would say matcher.group(1), matcher.group(2), and matcher.group(3) will give you what you want.