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如何使用Java正则表达式拆分此字符串

[英]How to split this string using Java Regular Expressions

I want to split the string 我想分割字符串

String fields = "name[Employee Name], employeeno[Employee No], dob[Date of Birth], joindate[Date of Joining]";

to

name
employeeno
dob
joindate

I wrote the following java code for this but it is printing only name other matches are not printing. 我为此编写了以下Java代码,但它仅打印其他匹配项不打印的名称。

String fields = "name[Employee Name], employeeno[Employee No], dob[Date of Birth], joindate[Date of Joining]";

Pattern pattern = Pattern.compile("\\[.+\\]+?,?\\s*" );

String[] split = pattern.split(fields);
for (String string : split) {
    System.out.println(string);
}

What am I doing wrong here? 我在这里做错了什么?

Thank you 谢谢

This part: 这部分:

\\[.+\\]

matches the first [ , the .+ then gobbles up the entire string (if no line breaks are in the string) and then the \\\\] will match the last ] . 匹配第一个[.+然后吞噬整个字符串(如果字符串中没有换行符),然后\\\\]将匹配最后一个]

You need to make the .+ reluctant by placing a ? 你需要做的.+通过放置一个不情愿? after it: 之后:

Pattern pattern = Pattern.compile("\\[.+?\\]+?,?\\s*");

And shouldn't \\\\]+? 而且不是\\\\]+? just be \\\\] ? 只是\\\\]吗?

The error is that you are matching greedily . 错误是您正在贪婪地进行匹配。 You can change it to a non-greedy match: 您可以将其更改为非贪婪匹配:

Pattern.compile("\\[.+?\\],?\\s*")
                      ^

http://gskinner.com/RegExr/?2sa45上有一个在线正则表达式测试器,当您尝试了解正则表达式以及如何将其应用于给定输入时,它将为您提供很多帮助。

WOuld it be better to use Negated Character Classes to match the square brackets? 使用否定字符类来匹配方括号会更好吗? \\[(\\w+\\s)+\\w+[^\\]]\\] \\ [((ww + \\ s)+ \\ w + [^ \\]] \\]

You could also see a good example how does using a negated character class work internally (without backtracking)? 您还会看到一个很好的示例,使用否定的字符类在内部如何工作(不回溯)?

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