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null = True的ForeignKey字段给出'NoneType'对象没有属性ID

[英]ForeignKey field with null=True gives 'NoneType' object has no attribute id

I am new to Django. 我是Django的新手。

I have the following models.py 我有以下型号。

from django.db import models
from django.contrib.auth.models import User
from django.utils import timezone
import os

def get_upload_path(instance, filename):
    return os.path.join(
      "folder_%d" % instance.folder.id, filename)

class Folder(models.Model):

    folder_name=models.CharField(max_length=100)
    parent_folder=models.ForeignKey('self', null=True, blank=True)
    folder_description=models.TextField(max_length=200)

        def __unicode__(self):
        return self.folder_name
class File(models.Model):

    folder=models.ForeignKey(Folder, null=True, blank=True)
    uploaded_file=models.FileField(upload_to=get_upload_path)
    pub_date = models.DateTimeField('date published',default=timezone.now())
    tag=models.ManyToManyField(FileTag)
    notes=models.TextField(max_length=200)
    uploader=models.ForeignKey(User)

    def __unicode__(self):
        return str(self.uploaded_file)

def filename(self):
        return os.path.basename(self.uploaded_file.name)

If I try to save a File object with folder attribute with null its gives me 'AttributeError' saying 'NoneType' Object has no attribute id 如果我尝试使用null属性保存具有文件夹属性的File对象,则会给我'AttributeError',提示'NoneType'对象没有属性ID

anyway model execute this method: 无论如何,模型执行此方法:

def get_upload_path (instance, filename): 
    return os.path.join ("folder_% d"% instance.folder.id, filename) 

which is trying to access folder, but folder is NoneType 试图访问文件夹,但文件夹为NoneType

you need something such 你需要这样的东西

def get_upload_path (instance, filename): 
    folder = instance.folder and instance.folder.id or 'default'
    return os.path.join ("folder_% d"% folder, filename) 

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