[英]Using regex to parse multiline string
This is the full string that I want to parse: 这是我要解析的完整字符串:
Response
--------
{
Return Code: 1
Key : <None>
Files : [
{
Return Code: 0
Data : 'Value' is 1
'Value' is two
This is third line of output
}
]
}
And this is how I want the parsed text to look like: 这就是我希望解析后的文本看起来像的样子:
'Value' is 1
'Value' is two
This is third line of output
I've tried messing with re.findall()
but I cannot get exactly what I want. 我已经尝试过re.findall()
但是我无法得到我想要的。
This is a python script which trys to parse using regex .. 这是一个python脚本,试图使用正则表达式进行解析。
import subprocess,re
output = subprocess.check_output(['staf', 'server.com', 'PROCESS', 'START', 'SHELL', 'COMMAND', "'uname'", 'WAIT', 'RETURNSTDOUT', 'STDERRTOSTDOUT'])
result = re.findall(r'Data\s+:\s+(.*)', output, re.DOTALL)[0]
print result
Output of script .. 脚本输出
[root@server ~]# python test.py
''uname'' is not recognized as an internal or external command,
operable program or batch file.
}
]
}
Option 1 选项1
If you want the three lines after Data:
, you can do something like this, capturing the three lines into Group 1: 如果要在Data:
之后添加三行,则可以执行以下操作,将三行捕获到组1中:
match = re.search(r"Data\s*:\s*((?:[^\n]*[\r\n]+){3})", subject)
if match:
result = match.group(1)
Option 2 选项2
If you want all the lines after Data:
before the first line that has a }
, change the regex to : 如果要在Data:
之后的所有行,在包含}
的第一行之前,将正则表达式更改为:
Data\s*:\s*((?:[^\n]*(?:[\r\n]+(?!\s*}))?)+)
Using the following regex, you'll find the three strings you want. 使用以下正则表达式,您将找到所需的三个字符串。
Notice that this depends heavily on how the response is formatted. 请注意,这在很大程度上取决于响应的格式。
>>> import re
>>> response = """
Response
--------
{
Return Code: 1
Key : <None>
Files : [
{
Return Code: 0
Data : 'Value' is 1
'Value' is two
This is third line of output
}
]
}"""
>>> re.findall(r"('Value'.*)\n(.*)\n(.*)\n.*}",response)
[("'Value' is 1", "'Value' is two", 'This is third line of output')]
You could also include the newline characters in the groups like this: 您还可以在这样的组中包括换行符:
>>> re.findall(r"('Value'.*\n)(.*\n)(.*\n).*}",response)
[("'Value' is 1\n", "'Value' is two\n", 'This is third line of output\n')]
Depends on how you want to process this afterward. 取决于您以后如何处理。
UPDATE 更新
How about this? 这个怎么样?
>>> re.findall(r"Data\s*:\s*(.*?)}",response,re.DOTALL)
["'Value' is 1\n'Value' is two\nThis is third line of output\n "]
This will find everything from the first 'Value' up untill the first '}'. 这将找到从第一个“值”到第一个“}”的所有内容。
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