Using regex to parse multiline string

Question

This is the full string that I want to parse:

Response
--------
{
  Return Code: 1
  Key        : <None>
  Files      : [
    {
      Return Code: 0
      Data       : 'Value' is 1
'Value' is two
This is third line of output
    }
  ]
}

And this is how I want the parsed text to look like:

'Value' is 1
'Value' is two
This is third line of output

I've tried messing with re.findall() but I cannot get exactly what I want.
This is a python script which trys to parse using regex ..

import subprocess,re
output = subprocess.check_output(['staf', 'server.com', 'PROCESS', 'START', 'SHELL', 'COMMAND', "'uname'", 'WAIT', 'RETURNSTDOUT', 'STDERRTOSTDOUT'])
result = re.findall(r'Data\s+:\s+(.*)', output, re.DOTALL)[0]
print result

Output of script ..

[root@server ~]# python test.py 
''uname'' is not recognized as an internal or external command,
operable program or batch file.

    }
  ]
}

Answer 1

Option 1

If you want the three lines after Data: , you can do something like this, capturing the three lines into Group 1:

match = re.search(r"Data\s*:\s*((?:[^\n]*[\r\n]+){3})", subject)
if match:
    result = match.group(1)

Option 2

If you want all the lines after Data: before the first line that has a } , change the regex to :

Data\s*:\s*((?:[^\n]*(?:[\r\n]+(?!\s*}))?)+)

Answer 2

Using the following regex, you'll find the three strings you want.

Notice that this depends heavily on how the response is formatted.

>>> import re
>>> response = """
Response
--------
{
  Return Code: 1
  Key        : <None>
  Files      : [
    {
      Return Code: 0
      Data       : 'Value' is 1
'Value' is two
This is third line of output
    }
  ]
}"""
>>> re.findall(r"('Value'.*)\n(.*)\n(.*)\n.*}",response)
[("'Value' is 1", "'Value' is two", 'This is third line of output')]

You could also include the newline characters in the groups like this:

>>> re.findall(r"('Value'.*\n)(.*\n)(.*\n).*}",response)
[("'Value' is 1\n", "'Value' is two\n", 'This is third line of output\n')]

Depends on how you want to process this afterward.

UPDATE

How about this?

>>> re.findall(r"Data\s*:\s*(.*?)}",response,re.DOTALL)
["'Value' is 1\n'Value' is two\nThis is third line of output\n    "]

This will find everything from the first 'Value' up untill the first '}'.