如何将String Iterator转换为元组列表

Question

How can

val s = Iterator("a|b|2","a|c|3")   

be converted to

List( (("a" , "b") , 2) , (("a" , "c") , 3)))

This is my current progress :

val v = s.map(m => m.split("|")(0))

How can I parse the String into its constituent parts so can be converted to a List of Tuples ?

Answer 1

您可以匹配从split返回的数组：

val v = s.map(_.split('|') match { case Array(a, b, n) => ((a, b), n.toInt) })