无法使用C＃读取xml文件

Question

I am trying to read a xml file using c#

XmlDocument doc = new XmlDocument();
doc.Load(@"/Rules/AssessmentRule.xml");
XmlNode node = doc.SelectSingleNode("/RuleName");
string URI = node.InnerText;
return URI;

I kept breakpoints in 2nd and 3rd line. I get error in the line below

doc.Load(@"/Rules/AssessmentRule.xml");

It says

Could not find a part of the path 'C:\\Program Files\\Rules\\AssessmentRule.xml'.

The folder structure of my project is, it is having the Rules folder in the same place as my class file

Answer 1

When running in debug the path is based from Debug settings, which defaults to bin\\debug unless you access the file with full path it will be relative to that folder(bin\\debug). [courtesy @miltonb]

so below are two solutions.

you can add that file into your VS project. then click on that file in VS go to properties set 'Copy to output directory' -> copy always. then just need to give the file name

or you get your project directory like this

string projectPath = Directory.GetParent(Directory.GetCurrentDirectory()).Parent.FullName;
string xmlLocation = @"Rules/AssessmentRule.xml";
String fullPath = Path.Combine(projectPath,xmlLocation);

Answer 2

If the file in your project folder Try this code for path

string wanted_path = Path.GetDirectoryName(Path.GetDirectoryName(System.IO.Directory.GetCurrentDirect‌​ory()));

then find the file on that path.

Answer 3

在调试中运行时，该路径基于“ bin \\ debug”，除非您使用完整路径访问该文件，该路径将相对于该文件夹。

Answer 4

You need to get the project directory, then append the xml path.

string projectPath = Directory.GetParent(Directory.GetCurrentDirectory()).Parent.FullName;
string xmlLocation = @"Rules/AssessmentRule.xml";
String fullPath = Path.Combine(projectPath,xmlLocation);

Answer 5

You should probably use an OpenFileDialog instead. It'll make your life a lot easier:

var openFile = new Microsoft.Win32.OpenFileDialog() {
    CheckFileExists = true,
    CheckPathExists = true,
    Filter = "XML File|*.xml"
};

if (openFile.ShowDialog() ?? false)
{
    XmlDocument doc = new XmlDocument();
    doc.Load(openFile.FileName);
    XmlNode node = doc.SelectSingleNode("/RuleName");
    string URI = node.InnerText;

    return URI;
}
else
{
    // User clicked cancel
    return String.Empty;
}