[英]Chess board using Recti
i was making a program to draw a chess board the code is 我正在编写一个程序来画一个棋盘,代码是
#include "glut.h"
void myDisplay(void);
void myInit(void);
int main(int argc, char ** argv)
{
glutInit(&argc, argv);
glutInitWindowSize(640, 480);
glutInitWindowPosition(100, 150);
glutCreateWindow("hello");
glutDisplayFunc(myDisplay);
myInit();
glutMainLoop();
return 0;
}
void myInit(void)
{
glClearColor(1, 1, 1, 0);
glColor3f(0, 0, 0);
glPointSize(10);
glutInitDisplayMode(GLUT_SINGLE | GL_RGB);
glMatrixMode(GL_PROJECTION);
glLoadIdentity();
gluOrtho2D(640, 0, 480, 0);
}
void myDisplay(void)
{
glClear(GL_COLOR_BUFFER_BIT);
int counter = 0;
for (GLint x = 0; x < 120; x += 15)
{
for (GLint y = 0; y < 120; y += 15)
{
counter++;
if (counter & 1 ){
glColor3f(.6, .6, .6);
}
else{
glColor3f(.2, .2, .2);
}
glRecti(x, y, (x + 15), (y + 15));
}//end of y
}//end of x
glFlush();
}
and the output was 和输出是
now if i just add the equal (=) sign to the condition in my (loops) in the myDisplay function it works fine but it also add one more row and one more colu. 现在,如果我只是在myDisplay函数的(循环)中的条件上添加等号 (=),它可以正常工作,但它还会增加一行和另一行。 so it's a new chess bored 9X9
所以这是一种新的无聊的国际象棋9X9
note: i already debug the program and the funny thing it works fine on the debug mode since it did switch between the conditions ... 注意:我已经调试了程序,有趣的是它在调试模式下可以正常工作,因为它确实在条件之间进行了切换...
It "works" when you use <=
of course, since then, you are drawing an odd number of rectangles per column. 当然,当您使用
<=
时,它将“起作用”,因为从那时起,每列将绘制奇数个矩形。 But if you draw the correct number of 8, you get an even number of invocations of your inner loop,hence counter will always be even when you start a new column. 但是,如果您绘制正确的数字8,则您对内部循环的调用次数将是偶数,因此即使您开始新的列,计数器也将始终为偶数。
That is due to the fact that counter & 1
is just not the right condition to make a checkerboard pattern. 这是由于
counter & 1
并不是制作棋盘格图案的正确条件。 The simplest approach in your case would be to drop counter
alltogether and just use something like ((x+y)/15) & 1
to check which type of field you are at. 在您的情况下,最简单的方法是将所有
counter
放在一起,并仅使用((x+y)/15) & 1
来检查您所处的字段类型。
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