[英]Pipe output of awk to sed in single command
I have a simple file like : 我有一个简单的文件,如:
a 123
b 234
In a second file, I want to replace a string by the value corresponding to a -> "123" in a single command . 在第二个文件中,我想用一个命令中与->“ 123”对应的值替换字符串。
Is there a way to pipe the result of grep "a" file1 | awk {print $2}
有没有一种方法来管道
grep "a" file1 | awk {print $2}
的结果? grep "a" file1 | awk {print $2}
to sed s/string/my_output/g file2
grep "a" file1 | awk {print $2}
到sed s/string/my_output/g file2
Here is an awk
这是一个
awk
cat file1
a 123
b 234
cat file2
cat
bad hat
awk -v FS="" 'FNR==NR {split($0,b," ");a[b[1]]=b[2];next} {for (i=1;i<=NF;i++) $i=a[$i]?a[$i]:$i}1' file1 file2
c 123 t
234 123 d h 123 t
How does it work. 它是如何工作的。
awk -v FS="" ' # By setting Field Separator to nothing, it works on one and one letter
FNR==NR { # This is true only for the first file (file1)
split($0,arr-b," ") # Split the data in first file (arr-b[1]=first filed, eks a, arr-b[2]=second field, eks 123
arr-a[arr-b[1]]=arr-b[2] # Store this to an array using field 1 as index. arr-a[a]=123 arr-a[b]=234 etc
next} # Skip to next record in file1
{ # Run this for file2
for (i=1;i<=NF;i++) # Loop trough on by on letter "c" "a" "t"
$i=arr-a[$i]?arr-a[$i]:$i} # Test the letter one by one if its found in array "arr-a", if so use data from array, if not keep value
1 # Since this always will be true, do default action "print $0" (print every line)
' file1 file2 # Read file1 and file2
If I interpret your question correctly, try 如果我正确解释了您的问题,请尝试
sed 's@^\(.*\) \(.*\)$@s/\1/\2/g@' SimpleFile > substitutions.file
sed -f substitutions.file 2ndFile > 2ndFile.tmp && mv 2ndFile.tmp 2ndFile
The first step will create a sed substitions file like 第一步将创建一个sed替换文件,例如
s/a/123/g
s/b/234/g
which when used as in line2 above, will substitute each a with 123, etc. 在上述第2行中使用时,将用123代替每个a,依此类推。
IHTH IHTH
You could do the following: 您可以执行以下操作:
grep a file1| awk '{print $2}' > tmp.txt
This will put '123' in a temporary file. 这会将“ 123”放入一个临时文件。 Then:
然后:
sed -f script.sed file2
Where the contents of script.sed is script.sed的内容在哪里
/string to replace/ {
r tmp.txt
d
}
This script replaces "string to replace" with the contents of tmp.txt. 此脚本用tmp.txt的内容替换“替换字符串”。
here's a pure-Awk solution. 这是一个纯Awk解决方案。 Put the dictionary in 'adict.dat' then pass your input file to the Awk command
将字典放在“ adict.dat”中,然后将输入文件传递给Awk命令
BEGIN {
while(( getline line < "adict.dat" ) > 0 ) {
$0 = line;
myvars[$1] = $2;
}
}
{
for (varname in myvars) {
gsub(varname, myvars[varname]);
}
print;
}
/bin/echo 'a x b y' | gawk -f arepl.awk
123 x 234 y
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