如何添加用户在 Python 中输入的一组数字？

Question

How do I add numbers in between two numbers the user inputted in Python 2.7. So a person would input 75 and 80 and I want my program to add the numbers in between those two numbers. I am very new to programming and python so any help would be awesome!

Answer 1

This example excludes 75 and 80. If you need to include them replace with print sum(range(n1,n2+1))

n1=input('Enter first number ')
n2=input('Enter second number ')
print sum(range(min(n1,n2)+1,max(n1,n2)))

Answer 2

@DSM is right!

n1=input('Enter first number ')
n2=input('Enter second number ')
print (n2-n1+1)*(n2+n1)/2

Answer 3

to capture user input use number1 = raw_input('Input number') . From there I'm not exactly sure what you mean from adding numbers between the two? If you want 76+77+78+79 in that example

number1 = raw_input('Input number')
number2 = raw_input('Second number')
result = 0
for n in range(int(number1)+1, int(number2)):
    result+=n
print result

Answer 4

Here's a quick sample that should handle a few different situations. Didn't go that in-depth since I don't know the scope of the situation. Realistically you should do some form of type-checking and loop until valid input is entered. However this should get you started:

def sumNums(a, b):
    total = 0
    if a < b:
        total = sum(range(a+1, b))
    elif b < a:
        total = sum(range(b+1, a))  
    return total

num1 = int(raw_input("First Number: "))
num2 = int(raw_input("Second Number: "))
print sumNums(num1, num2)

However I'm sure there's a more comprehensive way using lists and sum() but it seems like you only need a basic working example.

Answer 5

easy you just go

def add(x,y):
    if True:
        return add(x, y)
    else:
        return None


add([1,2,3,4][0], [1,2,3,4][2])