[英]how do i assign these config variables from file in a bash loop
i have a configuration file with definitions like: 我有一个配置文件,其定义如下:
[BEGIN 1]
age=16
sex=M
height=1.5
weight=20
[END 1]
...
[BEGIN 4]
age=17
sex=F
height=1.3
weight=40
[END 4]
I need to loop through these like so in another script: 我需要像在另一个脚本中那样遍历这些:
worker_exec $age $sex $height $weight -update | tee output.log
I was thinking if i only had one occurence in the config file i would remove the [BEGIN.. and [END.. lines and source it. 我在想如果我在配置文件中只出现一次,我会删除[BEGIN ..和[END ..]行并将其来源。 But now there are multiple definitions, how would i read this file and get those definitions in bash variables and use them?
但是现在有多个定义,我将如何读取该文件并在bash变量中获取这些定义并使用它们? I also thought to use temporary files, then it occured to me that extracting the N^(th) section is something i dont know how to do with awk
我还认为要使用临时文件,然后我想到提取N ^(th)节是我不知道如何使用awk的事情
End result is i can run 最终结果是我可以跑步
for item in ...# something here i dont get, maybe also unset any previous
# definitions in previous loop if neccessary.
do
worker_exec $age $sex $height $weight -update | tee output.log
done
If i understand what you want this should work. 如果我明白你想要什么,这应该工作。
Awk to format it Sets FS(Field Separator) to = Awk将其格式化将FS(Field Separator)设置为=
Sets ORS(Output Record Separator) to nothing 设置ORS(输出记录分隔符)为空
If it has [END
on line print new line If it does have [END
or [BEGIN
print line with a space(notice as ORS is nothing this does not print a new line) 如果它有
[END
在行上打印新行,如果它有[END
或[BEGIN
在行上打印空格(请注意,因为ORS为空,所以不会打印新行)
Then just read through the lines as they are in the correct order the full line can be passed to worker_exec as it will be resolved prior 然后只需按正确的顺序阅读各行,就可以将整行传递给worker_exec,因为它将在
Triple redirect is used to pass variable into a loop. 三重重定向用于将变量传递到循环中。
VARS=$(awk 'BEGIN {FS="=" ;ORS=""};/\[END/ {print"\n"} !/\[END/ && !/\[BEGIN/ {print $2" "}' test)
while read line; do
worker_exec $line -update | tee output.log
done <<< "$VARS"
Hope this helps :) 希望这可以帮助 :)
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