如何将输出分配给两个bash数组变量

Question

There are vaguely similar answers here but nothing that could really answer my question. I am at a point in my bash script where I have to fill two arrays from an output that looks like the following:

part-of-the-file1:line_32
part-of-the-file1:line_97
part-of-the-file2:line_88
part-of-the-file2:line_93

What I need to do is pull out the files and line numbers in there own separate arrays. So far I have:

read FILES LINES <<<($(echo $INPUTFILES | xargs grep -n $id | cut -f1,2 -d':' | awk '{print $1 " " $2}' with a modified IFS=':' but this doesn't work. I'm sure there are better solutions since I am NOT a scripting or tools wizard.

Answer 1

read cannot populate two arrays at a time like it can populate two regular parameters using word-splitting. It's best to just iterate over the output of your pipeline to build the arrays.

while IFS=: read fname lineno therest; do
  files+=("$fname")
  lines+=("$lineno")
done < <(echo $INPUTFILES | xargs grep -n "$id")

Here, I'm letting read do the splitting and discarding of the the tail end of grep 's output in place of using cut and awk .