如何使用 bash 将带有参数的 function 的 output 分配给变量？

Question

example (){
......
local var
......
return $var 
}

user_val=$(example $number1 $number2) 

I need user_val and i will it. I got error. Code can't detect the function when I try it this way.

Answer 1

@Barmar is correct. Replace return with echo in your function. Using var=$(...) assigns the output of the function to the variable.

When using return the value is saved in $? .