将sed集成到find xargs copy shell命令中

Question

I have a script that I use to copy all of the files in one folder and move them to a new folder... the line i use to do it looks like this

find "$SOURCEFOLDER" -type f | xargs -I {} ln {} "$ENDFOLDER/$TR_NEW_TORRENT_NAME/${basename}"

and it works perfectly

the thing is I'd like to also use sed to remove any brackets from the basename of the new file but i don't know how to incorporate the sed command

sed -e 's/\[[^][]*\]//g' FILE

how would I go about doing this? Is there a better or simpler way to do all the things I want?

Answer 1

I believe following will work for you:

find "$SOURCEFOLDER" -type f -exec bash -c "sed -e 's/\\[[^][]*\\]//g' {} ; xargs -I {} ln {} "$ENDFOLDER/$TR_NEW_TORRENT_NAME/${basename}" \\;

Idea is to combine the commands this ways:

another way is to use two -exec

find "$SOURCEFOLDER" -type f -exec sed -e 's/\[[^][]*\]//g' {}\; -exec ln {} "$ENDFOLDER/$TR_NEW_TORRENT_NAME/${basename}" \;

I hope this will help.

Answer 2

You can use -execdir option of find for this renaming and avoid xargs altogether:

find "$SOURCEFOLDER" -type f -execdir bash -c 'sed "s/\[[^][]*\]//g" <<< "$1";
    ln "$1" "$ENDFOLDER/$TR_NEW_TORRENT_NAME/${basename}"' - '{}' \;