需要帮助，使用find命令和xargs命令

Question

I'm trying to write a simple scripts that can mv every file within a folder to a folder generated from the current date. This is my initiatives.

#!/bin/bash

storage_folder=`date +%F` # date is generated to name the folder 
mkdir "$storage_folder" #createing a folder to store data 

find "$PWD" | xargs -E mv "$storage_folder" # mv everyfile to the folder

Answer 1

xargs is not needed. Try:

find . -exec mv -t "$storage_folder" {} +

Notes:

1. Find's -exec feature eliminates most needs for xargs .

2. Because . refers to the current working directoy, find "$PWD" is the same as the simpler find . .

3. The -t target option to mv tells mv to move all files to the target directory. This is handy here because it allows us to fit the mv command into the natural format for a find -exec command.

POSIX

If you do not have GNU tools, then your mv may not have the -t option. In that case:

find . -exec sh -c 'mv -- "$1" "$storage_folder"' Move {} \;

The above creates one shell process for each move. A more efficient approach, as suggested by Charles Duffy in the comments, passes in the target directory using $0 :

find . -exec sh -c 'mv -- "$@" "$0"' "$storage_folder" {} +

Safety

As Gordon Davisson points out in the comments, for safety, you may want to use the -i or -n options to mv so that files at the destination are not overwritten without your explicit approval.